Question 125760
Solve.
1) Square root of (3x-8) +4=6 
sqrt(3x-8) = 2
Square both sides to get:
3x-8 = 4
3x = 12
x = 4
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2)Find the distance between (1,-3)and(4,3)
distance = sqrt[(change in x)^2 + (change in y)^2]
distance = sqrt[(4-1)^2 + (3--3)^2]
distance = sqrt[9+36]
distance = sqrt(45)
distance = 3 sqrt(5)
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Cheers,
Stan H.