Question 125745
Start with the given system of equations:


{{{2x-y=8}}}

{{{x=2}}}








Let's solve for y on the first equation


{{{2x-y=8}}} Start with the given equation



{{{-y=8-2x}}}  Subtract {{{2 x}}} from both sides



{{{-y=-2x+8}}} Rearrange the equation



{{{y=(-2x+8)/(-1)}}} Divide both sides by {{{-1}}}



{{{y=(-2/-1)x+(8)/(-1)}}} Break up the fraction



{{{y=2x-8}}} Reduce



Now lets graph {{{y=2x-8}}} (note: if you need help with graphing, check out this <a href=http://www.algebra.com/algebra/homework/Linear-equations/graphing-linear-equations.solver>solver</a>)



{{{ graph( 600, 600, -10, 10, -10, 10, 2x-8) }}} Graph of {{{y=2x-8}}}



Now graph {{{x=2}}}


In order to graph {{{x=2}}}, simply draw a vertical line through the tick mark "{{{2}}}" on the x-axis

{{{drawing(500,500,-10,10,-10,10,
graph(500,500,-10,10,-10,10,0),
line(2,-20,2,20)
)}}} Graph of {{{x=2}}}



Add the graph of {{{x=2}}} to the graph of {{{y=2x-8}}}



{{{drawing(500,500,-10,10,-10,10,
graph(500,500,-10,10,-10,10,2x-8),
line(2,-20,2,20)
)}}} Graph of {{{y=2x-8}}} (red line) and {{{x=2}}} (black line)


From the graph, we can see that the two lines intersect at the point (2,-4)