Question 125737


Let's denote the first point (4,9) as *[Tex \Large \left(x_{1},y_{1}\right)]. In other words, *[Tex \LARGE x_{1}=4] and *[Tex \LARGE y_{1}=9]


Now let's denote the second point (8,17) as *[Tex \Large \left(x_{2},y_{2}\right)]. In other words, *[Tex \Large x_{2}=8] and *[Tex \Large y_{2}=17]




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{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula


{{{m=(17-9)/(8-4)}}} Plug in {{{y[2]=17}}},{{{y[1]=9}}},{{{x[2]=8}}},{{{x[1]=4}}}



{{{m=8/4}}} Subtract the terms in the numerator {{{17-9}}} to get {{{8}}}.  Subtract the terms in the denominator {{{8-4}}} to get {{{4}}}

  

{{{m=2}}} Reduce


  

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Answer:


So the slope of the line through the points (4,9) and (8,17) is {{{m=2}}}