Question 125732

{{{x+2y=0}}} Start with the given equation



{{{2y=0-x}}}  Subtract {{{ x}}} from both sides



{{{2y=-x}}} Simplify



{{{y=(-1/2)x}}} Divide both sides by 2 to isolate y



So the equation is now in slope-intercept form ({{{y=mx+b}}}) where the slope is {{{m=-1/2}}} and the y-intercept is {{{b=0}}}. Note: the equation really looks like {{{y=(-1/2)x+0}}}