Question 125707


One number ({{{x}}}) is {{{12}}} more than another ({{{y}}}):

{{{x = y + 12}}} 

{{{x}}} is the larger number
{{{y}}} is the smaller number

so, we have

{{{y + 2x = 36}}} .....substitute {{{x}}}

{{{y + 2(y + 12) = 36}}} 

{{{y + 2y + 24 = 36}}} 

{{{3y = 36 -24}}} 

{{{3y = 12}}} 

{{{y = 4}}} 


then

{{{x = y + 12}}} 

{{{x = 4 + 12}}} 

{{{x = 16}}} 

check:

{{{y + 2x = 36}}} 

{{{4+ 2*16 = 36}}} 

{{{4+ 32= 36}}} 

{{{36 = 36}}}