Question 125708
All you have to do is substitute.


{{{f(x)=5x-1}}}, then {{{cartoon(f(a-2) = 5(red(a-2))-1 = 5a-10-1=5a-11,f(a-2) = 5(a-2)-1 = red(5a-10)-1=5a-11,f(a-2) = 5(a-2)-1 = 5a-10-1=red(5a-11))}}}