Question 125441
What would the graph of the quadratic function with zeros 1/2 plus or minus sqrt7/3 look like ?
:
In order to graph it, you need the equation, find that:
x = {{{(1/2)+-sqrt(7/3)}}}
:
x - {{{1/2}}} = +/-{{{sqrt(7/3)}}}; subtract {{{1/2}}} from both sides
:
(x-{{{1/2}}})^2 = {{{7/3}}}; squared both sides
:
x^2 - 1x +{{{1/4}}} = {{{7/3}}}; FOILed
:
x^2 - 1x +{{{1/4}}} - {{{7/3}}} = 0; Subtracted {{{7/3}}} from both sides
:
x^2 - 1x +{{{3/12}}} - {{{28/12}}} = 0; use a common denominator
:
x^2 - 1x - {{{25/12}}} = 0
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Plot this equation from x = -2 to x = +3, it should look like this:
{{{ graph( 300, 200, -4, 6, -6, 6, x^2-x-(25/12)) }}}
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Could you follow this OK?