Question 125564
The length of a rectangle exceeds the width by 10cm.
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Original dimensions and area:
width = x cm ; length = x+10 cm ; Area = x(x+10) = x^2+10x cm^2
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If each dimension were increased by 3cm, the area would be no less than 111cm^2 more.
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New dimensions and area:
width= x+3 cm ; length= x+13 cm ; Area = (x+3)(x+13) cm^2
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What are the least possible dimensions of the rectangle?
Inequalities:
(x+3)(x+13) >=111
x^2+16x+39-111>=0
x^2+16x-72 >= 0
Graph the parabola to see where
it is >= 0 and x is positive:
x >= 3.661904...
Dimensions: width = 6.661904... ; length = 16.661904...

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Cheers,
Stan H.