Question 125452
Not sure if this is really going to answer the mail, but here is what I would do:


{{{D = (1-S^p)/(1-S)}}}


{{{D(1-S)=1-S^p}}}


{{{-1+D-DS=-S^p}}}


{{{1-D+DS=S^p}}}


{{{log(10,1-D+DS)=log(10,S^p)}}}


{{{log(10,1-D+DS)=p*log(10,S)}}}


{{{log(10,1-D+DS)/log(10,S)=p}}}