Question 125399
Let {{{n}}} = number of nickels
Let {{{d}}} = number of dimes
{{{n + d = 55}}}
{{{d = 55 - n}}}
{{{5n + 10d = 450}}}
{{{5n + 10(55 - n) = 450}}}
{{{5n + 550 - 10n = 450}}}
{{{-5n = -100}}}
{{{n = 20}}}
{{{d = 55 - n}}}
{{{d = 35}}}
There are 20 nickels and 35 dimes
check:
{{{5n + 10d = 450}}}
{{{5*20 + 10*35 = 450}}}
{{{100 + 350 = 450}}}
{{{450 = 450}}}
OK