Question 125188

To find the x-intercepts, let y=0 and solve for x


{{{x^2+x-6=0}}} 


{{{(x+3)(x-2)=0}}} Factor the left side (note: if you need help with factoring, check out this <a href=http://www.algebra.com/algebra/homework/playground/change-this-name4450.solver>solver</a>)




Now set each factor equal to zero:

{{{x+3=0}}} or  {{{x-2=0}}} 


{{{x=-3}}} or  {{{x=2}}}    Now solve for x in each case



So our answer is 

 {{{x=-3}}} or  {{{x=2}}} 



Notice if we graph {{{y=x^2+x-6}}}  we can see that the x-intercepts are {{{x=-3}}} and  {{{x=2}}} . So this visually verifies our answer.



{{{ graph(500,500,-10,10,-10,10,0, x^2+x-6) }}}