Question 125167


{{{3*x-2*y=12}}} Start with the given equation


Let's find the x-intercept


To find the x-intercept, let y=0 and solve for x:

{{{3*x-2*(0)=12}}} Plug in {{{y=0}}}


{{{3*x=12}}} Simplify


{{{x=12/3}}} Divide both sides by 3



{{{x=4}}} Reduce




So the x-intercept is *[Tex \Large \left(4,0\right)] (note: the x-intercept will always have a y-coordinate equal to zero)




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{{{3*x-2*y=12}}} Start with the given equation


Now let's find the y-intercept


To find the y-intercept, let x=0 and solve for y:

{{{3*(0)-2*y=12}}} Plug in {{{x=0}}}


{{{2*y=12}}} Simplify


{{{x=12/-2}}} Divide both sides by -2




{{{y=-6}}} Reduce




So the y-intercept is *[Tex \Large \left(0,-6\right)] (note: the y-intercept will always have a x-coordinate equal to zero)


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So we have these intercepts:

x-intercept: *[Tex \Large \left(4,0\right)]


y-intercept: *[Tex \Large \left(0,-6\right)]