Question 125122
I have actually never seen a question like this, but what it is asking you to do is solve for X and Y, and pretend Z is a number.  So your solutions for X and Y will have Z in them.
First, I would combine the 2 equations by subtracting the second from the first.  That way X will go away and I can solve for Y.  So (X-Y+Z=3)-(X-2Y-Z=5) =(X-Y+Z-Z+2Y+Z=3-5).
So Y+2Z=-2, so Y=-2-2Z.  Now plug that back into the first equation to solve for X.
X-Y+Z=3 becomes X-(-2-2Z)+Z=3, so X+2+2Z+Z=3, so X+2+3Z=3, so X=1-3Z.
So X=1-3Z, Y=-2-2Z is the solution.