Question 124949

{{{(2x-1)/6-2=(1/9)x-3}}} Start with the given equation




{{{(18)((2x-1)/6-2)=(18)((1/9)x-3)}}} Multiply both sides by the LCM of 18. This will eliminate the fractions  (note: if you need help with finding the LCM, check out this <a href=http://www.algebra.com/algebra/homework/divisibility/least-common-multiple.solver>solver</a>)




{{{3(2x-1)-36=2x-54}}} Distribute and multiply the LCM to each side




{{{6x-3-36=2x-54}}} Distribute again



{{{6x-39=2x-54}}} Combine like terms on the left side



{{{6x=2x-54+39}}}Add 39 to both sides



{{{6x-2x=-54+39}}} Subtract 2x from both sides



{{{4x=-54+39}}} Combine like terms on the left side



{{{4x=-15}}} Combine like terms on the right side



{{{x=(-15)/(4)}}} Divide both sides by 4 to isolate x




{{{x=-15/4}}} Reduce


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Answer:

So our answer is {{{x=-15/4}}}  (which is approximately {{{x=-3.75}}} in decimal form)