<PRE><B>Question 124935</B>
The length of a rectangle is 2 cm more than twice its width. If the perimeter of the rectangle is 52 cm, find the dimensions of the rectangle.&lt;br&gt;&lt;br&gt;

You already know that L=2w+2. So, put this into the formula for perimeter:
{{{52=2w+2(2w+2)}}}&lt;br&gt;&lt;br&gt;

Multiply:
{{{52=2w+4w+4}}}&lt;br&gt;&lt;br&gt;

Add:
{{{52=6w+4}}}&lt;br&gt;&lt;br&gt;

Subtract 4 from both sides:
{{{48=6w}}}&lt;br&gt;&lt;br&gt;

Divide both sides by 6:
{{{8=w}}}
Now you know the width. To find the length, use L=2w+2.
{{{L=2(8)+2}}}&lt;br&gt;&lt;br&gt;

Multiply:
{{{L=16+2}}}&lt;br&gt;&lt;br&gt;

Add:
{{{L=18}}}&lt;br&gt;&lt;br&gt;

So, the length is 18, and the width is 8.</PRE>