Question 124919
The general equation of a straight line is
{{{y = mx + b}}} where {{{m}}}  is the slope 
and {{{b}}} is the y-intercept
I know the slope, {{{m = 3}}} and a certain point P(-4, -17)
{{{-17 = 3*(-4) + b}}}
solve for {{{b}}}
{{{-17 = -12 + b}}}
{{{b = -5}}}
The equation is
{{{y = 3x - 5}}} answer