Question 19001
Okay, I'm not sure if you are asking to solve
{{{(6/5)=n+(10/4)}}} or {{{(6/5)=(n+10)/(4)}}}
but basically, in either one, the goal is to have the variable on one side of the equal sign and the constant on the other.  You do this by using the inverse (ie. opposite)operations.

To solve {{{(6/5)=n+(10/4)}}}
The first step is to get your constants all on one side.  The easiest way for this problem is to subtract {{{10/4}}} from both sides, giving you
{{{(6/5)-(10/4)=n+(10/4)-(10/4)}}}
The addition and subtraction on the n side cancel each other, leaving
{{{(6/5)-(10/4)=n}}}
Next find the lowest common denominator (LCD) of {{{6/5}}} and {{{10/4}}} and convert the fractions, giving you {{{(24/20)-(50/20)=n}}}
Now just calculate the subtraction and reduce to lowest terms.

To solve {{{(6/5)=(n+10)/(4)}}} you use the same concepts.  Just remember that multiplication and division are inverse to each other, addition and subtraction are inverse to each other and that all fractions are division problems.

I hope this helps!