Question 124896




{{{2x=-4y-16}}} Start with the second equation



{{{x=(-4y-16)/2}}} Divide both sides by 2



{{{x=(-4y)/2-(16)/2}}} Break up the fraction



{{{x=-2y-8}}} Reduce



Now let's solve the system 



{{{x+2y=-6}}}
{{{x=-2y-8}}}


by substitution




{{{-2y-8+2y=-6}}}  Plug in {{{x=-2y-8}}} into the first equation. In other words, replace each {{{x}}} with {{{-2y-8}}}. Notice we've eliminated the {{{x}}} variables. So we now have a simple equation with one unknown.





{{{-8=-6}}} Combine like terms on the left side



{{{0=-6+8}}}Add 8 to both sides



{{{0=2}}} Combine like terms on the right side




Since this equation is <font size=4><b>never</b></font> true for any y value, this means there are no solutions.