Question 124829
You have two equations, each of which is going to graph to two straight lines.


{{{abs(x-1)=5}}} => {{{x-1=5}}} or {{{x-1=-5}}} => {{{x=6}}} or {{{x=-4}}}


{{{abs(y)=3}}} => {{{y=3}}} or {{{y=-3}}}


{{{y=3}}} is a horizontal line where every ordered pair representing a point on the line has a y-coordinate of 3.  Similarly, the ordered pairs describing {{{y=-3}}} all have y-coordinates of -3.


{{{x=6}}} is a vertical line such that all of the ordered pairs have an x-coordinate of 6.  The two horizontal lines will intersect this vertical line at the points (6,3) and (6,-3), giving us two vertices of the quadrilateral.


{{{x=-4}}} is a vertical line such that all of the ordered pairs have an x-coordinate of -4.  The two horizontal lines will intersect this vertical line at the points (-4,3) and (-4,-3), giving us the other two vertices.


{{{drawing(400,400,-7,8,-7,7,grid(1),
green(line(-7,3,8,3),
line(-7,-3,8,-3),
line(-4,7,-4,-7),
line(6,7,6,-7)),
locate(6.1,2.9,A(6,3)),
locate(6.1,-3.1,B(6,-3)),
locate(-3.9,2.9,C(-4,3)),
locate(-3.9,-3.1,D(-4,-3))
)}}}