Question 124686
{{{2(b^(1/3)) + 5 = 15 }}}


{{{2(root(3,b)) = 15 - 5 }}}


{{{2b^1/3 + 5 = 15 }}}


{{{2(root(3,b)) = 10 }}}


{{{(root(3,b)) = 10/2 }}}


{{{(root(3,b)) = 5 }}}…..rise to the third power


{{{(root(3,b))^3 = 5^3 }}}…..


{{{b = 125}}}…..


8. {{{-4(s^(-3/5)) - 1 =31}}}


{{{-4(root(5,s^3)) =31 + 1}}}



{{{-4(root(5,s^3)) =32}}}


{{{(root(5,s^3)) =32/-4}}}


{{{(root(5,s^3)) = -8}}}


{{{(root(5,s^3))^5 = (-8)^5}}}


{{{s^3 = (-8)^5}}}.............


{{{s = root(3, (-8)^5) }}}.............


{{{s = root(3, (-8)^3*(-8)^2)  }}}.............


{{{s = (-8)root(3,64)}}}.............


{{{s = (-8)root(3,4^3)}}}.............


{{{s = (-8)4}}}.............


{{{s = -32}}}.............