Question 124427
160x=3x + the sqaure root of 50x+9000
:
160x-3x=the square root of 50x + 9000
which is:
157x = sqrt(50x+9000)
:
Square it:
24649x^2 = 50x + 9000
: 
Arrange as a quadratic equation
24649x^2 - 50x - 9000 = 0
:
you have to use the quadratic formula to solve it:
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
In this equation a=24649; b=-50; c=-9000
{{{x = (-(-50) +- sqrt(-50^2- 4 * 24649 * -9000 ))/(2*24649) }}}
: 
{{{x = (50 +- sqrt(2500 - (-887364000) ))/(49298) }}}
:
{{{x = (50 +- sqrt(2500 + 887364000 ))/(49298) }}}
:
{{{x = (50 +- sqrt(887336500))/(49298) }}}
Two solutions:
{{{x = (50 + 29788.7)/(49298) }}}
{{{x = (29838.7)/(49298) }}}
x = +.605
and
 {{{x = (50 - 29788.7)/(49298) }}}
{{{x = (-29738.7)/(49298) }}}
x = -.603
:
I checked these solutions on a Ti83 graphing calc. You can confirm it yourself
by substitution in the original equation