<PRE><B>Question 124564</B>
The sum of two numbers is 63.  The second is 6 more than 2 times the first.  What are the two numbers?&lt;br&gt;&lt;br&gt;

Ok, so you know that your second number is 2x+6. If you plug that and the 63 into an equation, you get:
{{{63=x+2x+6}}}&lt;br&gt;&lt;br&gt;

Add:
{{{63=3x+6}}}&lt;br&gt;&lt;br&gt;

Subtract 6 from both sides:
{{{57=3x}}}&lt;br&gt;&lt;br&gt;

Divide both sides by 3:
{{{19=x}}}&lt;br&gt;&lt;br&gt;

So now you know your first number. To find the second, use 2x+6.
{{{2(19)+6}}}&lt;br&gt;&lt;br&gt;

Multiply:
{{{38+6}}}&lt;br&gt;&lt;br&gt;

Add:
{{{44}}}&lt;br&gt;&lt;br&gt;

So, your first number is 19, and your second number is 44.&lt;br&gt;&lt;br&gt;

To check, simply plug the numbers in:
{{{63=19+44}}}&lt;br&gt;&lt;br&gt;

Add:
{{{63=63}}}</PRE>