Question 124304
{{{(5g)^2/(5g)^15}}} = 
The exponent is outside the bracket therefore it is the same as:
{{{(5^2g^2)/(5^15g^15)}}} 
:
Exponents are subtracted when dividing therefore:
{{{1/(5^(15-2)*g^(15-2))}}} = {{{1/(5^13*g^13))}}} = {{{1/((5g)^13)}}}
you could also write it {{{(5g)^-13}}}