Question 124539
{{{N = -0.00006x^3+0.006x^2-0.1x+1.3}}} Substitute x = 50
{{{N = -0.00006(50)^3+0.006(50)^2-0.1(50)+1.3}}}
{{{N = -7.5+15-5+1.3}}}
{{{N = 3.8}}} round to the nearest million...
{{{N = 4}}}Million, approximately.
{{{N = -0.00006x^3+0.006x^2-0.1x+1.3}}} Substitute x = 60
{{{N = -0.00006(60)^3+0.006(60)^2-0.1(60)+1.3}}}
{{{N = -12.96+21.6-6+1.3}}}
{{{N = 3.94}}} Round to the nearest million...
{{{N = 4}}}Million, approximately.