Question 124405

a)



Let's evaluate {{{f(-2)}}}



{{{f(x)=x^3+2x^2-7x+9}}} Start with the given function.



{{{f(-2)=(-2)^3+2(-2)^2-7(-2)+9}}} Plug in {{{x=-2}}}. In other words, replace each x with -2.



{{{f(-2)=(-8)+2(-2)^2-7(-2)+9}}} Evaluate {{{(-2)^3}}} to get -8.



{{{f(-2)=(-8)+2(4)-7(-2)+9}}} Evaluate {{{(-2)^2}}} to get 4.



{{{f(-2)=(-8)+8-7(-2)+9}}} Multiply 2 and 4 to get  8



{{{f(-2)=(-8)+8+14+9}}} Multiply -7 and -2 to get  14



{{{f(-2)=23}}} Now combine like terms



-----------Now let's evaluate another value---------


b)


Let's evaluate {{{f(0)}}}



{{{f(x)=x^3+2x^2-7x+9}}} Start with the given function.



{{{f(0)=(0)^3+2(0)^2-7(0)+9}}} Plug in {{{x=0}}}. In other words, replace each x with 0.



{{{f(0)=(0)+2(0)^2-7(0)+9}}} Evaluate {{{(0)^3}}} to get 0.



{{{f(0)=(0)+2(0)-7(0)+9}}} Evaluate {{{(0)^2}}} to get 0.



{{{f(0)=(0)+0-7(0)+9}}} Multiply 2 and 0 to get  0



{{{f(0)=(0)+0+0+9}}} Multiply -7 and 0 to get  0



{{{f(0)=9}}} Now combine like terms



-----------Now let's evaluate another value---------


c)


Let's evaluate {{{f(2)}}}



{{{f(x)=x^3+2x^2-7x+9}}} Start with the given function.



{{{f(2)=(2)^3+2(2)^2-7(2)+9}}} Plug in {{{x=2}}}. In other words, replace each x with 2.



{{{f(2)=(8)+2(2)^2-7(2)+9}}} Evaluate {{{(2)^3}}} to get 8.



{{{f(2)=(8)+2(4)-7(2)+9}}} Evaluate {{{(2)^2}}} to get 4.



{{{f(2)=(8)+8-7(2)+9}}} Multiply 2 and 4 to get  8



{{{f(2)=(8)+8-14+9}}} Multiply -7 and 2 to get  -14



{{{f(2)=11}}} Now combine like terms