Question 124254
For a, all we have to do is plug in zero for all values of x.


{{{0^2}}} - 2(0) +1


So a is 1.


For b, we just have to set the equatin equal to zero and solve.


{{{x^2}}} - 2x + 1 = 0


In order to solve for the values of x, we must factor.


{x - 1)(x - 1) = 0


So for b, x = 1