<PRE><B>Question 124331</B>
Evaluate the expression and write the result in the form a + bi. 

1/(2-4i)-1/(6-2i)

[6-2i-(2-4i)]/[(2-4i)(6-2i)]

= (4+2i)/(12-8-28i)
= (4+2i)/(4-28i)
Reduce:
= (2+i)/(2-14i)
Multiply numerator and denominator by (2+14i) to get:

=[(2+i)(2+14i)]/[200]

= [(4-14+30i)]/200

= [-10+30i]/200

= (-10/200) + (30/200)i

= -0.05 + 0.15i
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Cheers,
Stan H.

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