Question 124322
Write the equation y=-1/3x^2+6x+2 in transformational form . State the vertex :)
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Vertex occurs when x = -b/2a = -6/(2*(-1/3))= 9
f(9)= (-1/3)(9^2)+6*9+2 = -27+54+2 = 29
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Vertex:(9,29)
{{{graph(400,300,-20,40,-50,40,(-1/3)x^2+6x+2)}}}
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Cheers,
Stan H.