Question 124293
using this function f(x) =x^2 +4x +1, find h, the x-coordinate of the vertex of this parabola,using a graph.
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The max or min point occurs when x=-b/2a = -4/(2*1) = -2
Therefore h=-2
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substitute the two integers immediately to the left and right of h into the function to find the corresponding y. fill in following table. make sure the x- values are in increasing order in your table. 
If x=-4, f(-4) = (-4)^2+4*4+1 = 13
If x=-3, f(-3) = (-3)^2+4*-3+1 =-2
If x=-2, f(-2) = (-2)^2+4*-2+1 =-3
If x=-1, f(-1) = (-1)^2+4*-1+1 =-2
If x=0 , f(0)  = (0)^2+4*0+1 = 1
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{{{graph(400,300,-10,10,-10,10,x^2+4x+1)}}}
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Cheers,
Stan H.