Question 124297
{{{3+abs(2y-1)>=1}}} Start with the given inequality



{{{abs(2y-1)>=-2}}} Subtract 3 from both sides.


Since the absolute value is <b>always</b> positive, this means that {{{abs(2y-1)>=-2}}} is <b>always</b> true for any y values. So any value of y will work which means that there are an infinite number of solutions