<PRE><B>Question 124074</B>
Artic Anitfreeze is 18% alcohol and Frost No More is 10% alcohol. How many liters of each should be mixed to get 20L of a mixture that is 15% alcohol?
:
Let x = amt of arctic
then
(20-x) = amt of frost
:
.18x + .10(20-x) = .15(20)
:
.18x + 2 - .10x = 3
:
.18x - .10x = 3 - 2
:
.08x = 1
x = {{{1/.08}}}
x = 12.5 liters of arctic r
and
20 - 12.5 = 7.5 liters of frost
;
:
Check solution
.18(12.5) + .10(7.5) = .15(20)
 2.25 + .75 = 3; confirms our solution
:
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