Question 124188
{{{(2/3)(y+2)  -  (5/6)(y-1) = (5/4)(y-3) - 4}}}.....multiply both sides by {{{12}}}

{{{(2/3)12(y+2)  -  (5/6)12(y-1) = (5/4)12(y-3) - 4*12}}}.....

{{{(2/cross(3))cross(12)4(y+2)  -  (5/cross(6))cross(12)2(y-1) = (5/cross(4))cross(12)3(y-3) - 4*12}}}.....

{{{2*4(y+2)  -  5*2(y-1) = 5*3(y-3) - 4*12}}}.....


{{{8(y+2)  -  10(y-1) = 15(y-3) - 48}}}.....

{{{8y + 16  - 10y + 10 = 15y - 45 - 48}}}.....

{{{8y - 10y - 15y = - 45 - 10 -16 - 48}}}.....

{{{- 17y = - 119}}}.....

{{{y = - 119/-17}}}.....

{{{y = 7}}}.....


check

{{{(2/3)(7+2)  -  (5/6)(7-1) = (5/4)(7-3) - 4}}}.....

{{{(2/cross(3))cross((9))3  -  (5/cross(6))cross((6)) = (5/cross(4))cross((4)) - 4}}}.....

{{{2*3  -  5*1 = 5*1 - 4}}}.....

{{{6  -  5 = 5 - 4}}}.....

{{{1 = 1}}}.....