Question 124257
{{{f(x)=x^2-2x+1}}}

{{{f(0)=0^2-2(0)+1=1}}}


{{{x^2-2x+1=0}}}
{{{(x-1)(x-1)=0}}}

Therefore if {{{f(x)=0}}} then {{{x = 1}}} or {{{x = 1}}}