Question 123866
If you have 5 consecutive integers, call the first one x, then the second is x + 1, the third is x + 2, etc.


The sum of these 5 numbers divided by 5 is 12, so their sum must be 60, so:


{{{x+(x+1)+(x+2)+(x+3)+(x+4)=60}}}
{{{5x+10=60}}}
{{{5x=50}}}
{{{x=10}}}


Therefore the numbers are 10, 11, 12, 13, and 14.  The least is 10 and the greatest is 14.  Their sum is 24.