Question 123857
To put a quadratic equation in standard form, it must follow the format:
{{{y=ax^2+bx+c}}}
To put the given into standard form, we must distribute 3 with {{{(x-2)(x-2)}}}. ({{{(x-2)(x-2)}}}={{{(x-2)^2}}}.) If you do it, you should come up with {{{-3x^2+12x-12}}}. The only thing left to do is to add 5 to 12 in order to simplify it. In conclusion, the equation {{{f(x)=-3(x-2)^2+5}}} in standard form is {{{y=3x^2+12x-17}}}.