Question 123845
The given equations are:


2x + 4y = -6  ------------------(1)


x - 3y = 7  --------------------(2)


The 2nd equation can be re-written as:  x = 3y + 7 --------(3)


Substituting the 3rd eqn in the first equation we get:


2(3y + 7) + 4y = - 6 


using distributive property,


6y + 14 + 4y = - 6


10y + 14 = - 6


10y = -6 - 14 


10y = -20


==> y = {{{-(20/10) }}}


==> y = - 2


Now by back substitution,in equation(3) we get: 


x = 3y + 7


x = 3(-2) + 7 


x = -6 + 7


x = 1


thus the solution.

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