Question 123815
Let x = number of cows  (4 legs each)
y= number of chickens   (2 legs each)


x+y=45
4x+2y=106

Solve the system by multiplying first equation by -2:

-2x-2y=-90
4x+2y=106


Add the equations together:
2x=16
x= 8 cows
45-8=37 chickens


Check:
4*8+2*37
32+74=106 total legs


R^2