Question 123806
You can do this algebraically or graphically.  What is your choice?  I think the easiest way is graphical.


{{{graph(300,300,-6,6,-10,10, x^2-6x+2) }}}

It looks like the minimum value of f(x) is y=-7.


Try algebraically to confirm this answer:
y=x^2-6x+2


There are several ways, probably the easiest of which is to find {{{x=-b/(2a) }}}, where a is the coefficient of x^2 and b is the coefficient of x.  Therefore, a=1, b=-6, so {{{x=-b/(2a) =6/2=3}}}


{{{y=x^2-6x+2}}}, where x=3
{{{y=3^2-6*3+2}}}
{{{y=9-18+2}}}
{{{y=-7}}} is the minimum value


R^2