Question 123806
Determine the maximum or minimum value of the quadratic function. 
f(x)=x^2-6x+2
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max or min occurs at x = -b/2a = 6/2 = 3
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f(3) = 3^2-6*3+2 = -7
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minimum at (3,-7)
{{{graph(400,300,-10,10,-10,10,x^2-6x+2)}}}
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Cheers,
Stan H.