Question 123668
Question:

{{{(x^3+2x^2+3x-6)/(x-1)}}}

{{{(n^3-27)/(n-3)}}}



Answer:


{{{(x^3+2x^2+3x-6)/(x-1)}}}


Here the denominator can be re-written as, 


{{{ ((x^2 +3x +6)(x-1))/(x-1)}}}



==> {{{(x^2 +3x +6)}}}, where (x-1) will get cancelled..

So the simplified answer is, {{{x^2 +3x +6}}}





{{{(n^3-27)/(n-3)}}}


This can be written as, {{{ (n^3 -3^3)/(n-3)}}}



==> {{{(n-3)(n^2 + 3n + 9)/(n-3)}}}



==> {{{n^2 + 3n + 9}}}, which is the simplified answer...




Hope you found the explanation useful.




Regards.



Praseena.