Question 123676
s^2-15s+50
All we have to do is to write the formula down and replace the values.
as^2+bs+c=0 in our case a is 1, b is -15 and c is 50.
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} would result in
{{{x = (-(-15) +- sqrt( (-15)^2-4*1*50 ))/(2*1) }}} 
so +15+-sqrt( 225-200)) /2 =
so one solution is (15+5)/2 and the second solution is (15-5)/2 so x1=10 and x2=5 Let me know if you have prblems understanding it.
Thank-you.