Question 123682
x, x+1, x+2 are the integers.
2x+6(x+1)+3(x+2)=133
2x+6x+6+3x+6=133
11x=133-12
11x=121
x=121
11x=11 answer for the first integer.
11=1=12
11+2=13
proof:
2*11+6*12+3*13=133
22+72+39=133
133=133