Question 123651
price * # of units = revenues.
Let x= # of price reductions
(320-11x)*(12+2x)=5166
-22x^2+508x+3840=5166
-22x^2+508x-1326=0
-11x^2+254x-663=0
x=3, x=20.091
320-11*3= $287. Ans.
.
Check:
(320-11*3)*(12+2*3)
=287*18
=5166
.
The other answer is also correct but the number of price reductions is not even.
The sales price would be $99.
.
Ed

*[invoke solve_quadratic_equation -11, 254, -663]