Question 18836
1) {{{(3x-8)^2 = 16}}} Take (extract) the square root of both sides.
{{{sqrt((3x-8)^2) = sqrt(16)}}}
{{{(3x-8) = 4}}} Add 8 to both sides. Note: When you take the square root, you really get two answers...one is + and the other is -, so:
{{{3x-8 = 4}}} or {{{3x-8 = -4}}}
{{{3x = 12}}} Divide both sides by 3.
{{{x = 4}}}

{{{3x-8 = -4}}} Add 8 to both sides.
{{{3x = 4}}} Divide both sides by 3.
{{{x = 4/3}}}  

2)  
{{{6x^2 = 150}}} First, divide both sides by 6.
{{{x^2 = 25}}} Now take the square root of both sides.
{{{sqrt(x^2) = sqrt(25)}}}
{{{x = 5}}} or {{{x = -5}}}