Question 123441
Let x= # of five-point problems, y= # of two-point problems


Since there are 38 problems, this means we have the first equation {{{x+y=38}}}


Also, since the total sum of the five-point and two-point problems is 100, this tells us that the second equation is {{{5x+2y=100}}}



So we have the system


{{{x+y=38}}}

{{{5x+2y=100}}}





*[invoke solving_linear_system_by_substitution 1, 1, 38, 5, 2, 100]



So there are 8 five-point problems and 30 two-point problems