Question 123394
To find the axis of symmetry, we can use this formula 


{{{x=-b/2a}}} where "b" is the x coeffficient and "a" is the {{{x^2}}} coefficient



So by looking at {{{x^2- 5x + 3}}} we can see that {{{a=1}}} and {{{b=-5}}}


{{{x=-b/2a}}}  Start with the given formula



{{{x=-(-5)/2(1)}}} Plug in {{{a=1}}} and {{{b=-5}}}



{{{x=5/2(1)}}} Negate -5 to get 5



{{{x=5/2}}} Multiply



So the axis of symmetry is {{{x=5/2}}} which is {{{x=2.5}}} in decimal form