Question 123158
A forester mixes gasoline and oil to make 2 gallons of mixture for his two cycle chain-saw engine. This mixture is 32 parts gasoline and 1 part two cycle oil. How much gasoline must be added to bring the mixture to 40 parts gasoline and one part oil?
:
The total parts in the original mixture would be: 32 + 1 = 33 parts
The total parts in the new mixture will be: 40 + 1 = 41 parts
{{{1/33}}} of it is oil
:
{{{1/33}}}*2 = {{{1/41}}}(x+2)
:
Cross multiply
33(x+2) = 41(2)
33x + 66 = 82
33x = 62 - 66
33x = 16
x = 16/33
x = .48 gal, say, half gallon of gasoline required
:
:
Check:
 {{{1/33}}}*2 = .06
{{{1/41}}}*2.5 = .06