Question 123224
The area of a circle is equal to,
{{{A=((pi)D^2)/4}}}
{{{((pi)D^2)/4=(pi)(9y^2 + 78y + 169)}}}
{{{D^2=4(9y^2 + 78y + 169)}}}
{{{D^2=4(3y+13)^2}}}
{{{D=2(3y+13)}}} and {{{D=-2(3y+13)}}}