Question 123314
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Discussion
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The rule for exponents that applies to all three of your problems is this:


{{{b^(-n)=1/b^n}}}


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Solution
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1. {{{(3/7)^-2=1/(3/7)^2=(7/3)^2=49/9}}}


2. {{{(4/3)^-4=1/(4/3)^4=(3/4)^4=81/256}}}


3. {{{p(q^-2)(r^-3)=p/(q^2*r^3)}}}