Question 123137
Consider the function f(x)=x^2+4x+1
a) Find h, the x-coordinate of the vertex of this parabola.
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 h is the x-coordinate of the max or min pt which occurs 
when x = -b/2a.
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h = -b/2a = -4/(2*1) = -2
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b) Substitute the two integers immediately to the left and right of H into the function to find the corresponding Y. Fill in the table below. Make sure your X-values are in increasing order in your table.
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If x = -4, y = (-4)^2+4*-4+1 =  1
If x = -3, y = (-3)^2+4*-3+1 = -2
If x = -2, y = (-2)^2+4*-2+1 = -3
If x = -1, y = (-1)^2+4*-1+1 = -2
If x = 0 , y = (0)^2 + 4*0+1 =  1
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{{{graph(400,300,-10,10,-10,10,x^2+4x+1)}}}
Cheers,
Stan H.